Identify the major product $A$ in the following reaction sequence:
$CH_3-CH=CH-CH_3$ $\xrightarrow[CCl_4]{Br_2}$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH} (A)$

  • A
    $H_2C = CH - CH = CH_2$
  • B
    $CH_3 - C \equiv C - CH_3$
  • C
    $CH_3 - CH_2 - C \equiv CH$
  • D
    $CH_3 - CH = C = CH_2$

Explore More

Similar Questions

$C_6H_5 - C \equiv C - CH_3 \xrightarrow{HgSO_4, H_2SO_4} A$

The compound $C_3H_4$ has a triple bond,which is indicated by its reaction with

$Ph-CH=CH-Ph$ $\xrightarrow[CCl_4]{Cl_2} X$ $\xrightarrow{2NaNH_2} Y$ $\xrightarrow[BaSO_4]{H_2+Pd} Z$. Product $Z$ is

Difficult
View Solution

The final product obtained by heating ethyne in the presence of $HgSO_4$ and dilute $H_2SO_4$ at $333 \ K$ is .........

What is the product $A$ in the given reaction?
$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo